Most of the JEE Main aspirants must be aware of the fact that JEE Main Rank List is prepared after finding a composite score of JEE Main scores and Normalized Marks of Class XII in the ratio of 60:40. But very few know what actually is this normalization procedure and how nromalised score for class 12 results are calculated. JEE Main Merit Ranks form the basis of the admissions to undergraduate engineering courses at prestigious 31 NITs, 18 IIITs, 18 GFTIs and many other engineering institutions across India.Let's first understand a few concepts first.Percentage of marks and Percentile are though related but completely differentThe Percentage of marks and Percentile are totally different entities. Percentage is your marks out of a total of 100, whereas percentile score of a candidate reflects percentage of candidates scoring below a particular candidate in that exam.Calculation of percentile of a candidate:The percentile score of a candidate shows the score of the candidate with respect to the number of students.Thus we calculate the percentile score as below:Number of candidates in the group with aggregate marks less than the candidate x 100Total number of the candidates in the groupLetu2019s understand it more clearly with the help of few examples-Suppose in a particular board, the total number of candidates registered is 13918 and number of candidates appeared is 13711, the percentile of the candidate will be calculated in the following way-Example 1: Where a student has scored 50% in the exam and there are 2218 candidates, who have scored less than the candidates, i.e., less than 50%:2218u00a0 x 100 = 16.1813711Here, the percentile score of the candidate from exam is 16.18 while his/her percentage in the exam is 50%.Example 2: Where a student has scored 60% in the exam and there are 6865 candidates, who have scored less than the candidates, i.e. less than 60%:6865 x 100 = 50.0713711Here, the percentile score of the candidate is 50.07 while his/her percentage is 60%.Example 3: Where a student has scored 90% in the exam and there are 13615 candidates, who have scored less than the candidates, i.e. less than 90%:13615 x 100 = 99.313711Here, the percentile score of the candidate from the exam is 99.3 while his/her percentage is 90%.Subjects considered for Percentile Score:Five subjects will be taken into account for calculation of percentile and normalization of qualifying examination marks for paper 1 (B.E./B. Tech.) and paper 2 (B. Arch./B. Planning) of JEE Main.These subjects are:Language,Physics,Mathematics,Any one of (Chemistry, Biology, Biotechnology, Technical Vocational Subject),Any other subjectNote : In case a candidate has appeared in six subjects in the qualifying examination, the subject (fifth or sixth) with better marks will be considered.Candidates, who appear for improvement, will have to appear for all the subjects and not one or two which they wish to improve in.Important: Candidates, who are appearing in the improvement examination to improve their qualifying examination marks, will get only one chance to inform JEE (Main) Unit as to which year qualifying examination marks have to be considered for the purpose of declaration of final merit of JEE Main.Considerations for JEE Main & JEE Advanced:The percentile score a candidate gets in the board will mainly contribute to normalized marks to be used for the Merit Ranks of JEE Main and for qualifying for JEE Advanced.Candidates may note that the normalized qualifying examination marks will be based on the position of the candidate in his/her respective board (i.e. the above mentioned percentile score).It is important to note here that the weightage of normalized qualifying examination marks is only for deciding ranking of JEE Main for admissions to all Centrally Funded Technical Institutions (CFTIs)/ NITs/IIITs but not for IITs.Factors used in calculation of normalized qualifying examination marks:JEE Main Marks of all canddiates from the same board whose subject combinations meet the eligibility criteria of JEE MainJEE Main Marks of all candidates (on All India Basis) whose subject combinations meet the eligibility criteria of JEE Main students in JEE MainProcedure for Normalization of Class XII marks for JEE Main Rank Calculation:For your easy understanding, we bring you step-by-step process to calculate your normalised score of class XII marks.Normalised score of your class XII marks is actually the average of two JEE Main scores. what are these two JEE Main scores? The two JEE Main scores are derived by directly linking your Class XII Results to overall JEE Main Results.Here is how?Step 1: On the basis of your Class XII results, your percentile is calculated. You can calculate your percentile by using the formula below-Number of candidates in your board with aggregate marks less than you*100Total number of candidates in the groupu00a0Example:Let's assume that your score is 60 percent from a particular board where a total of 13,711 candidates are eligible for JEE Main. Also suppose number of canddiates scoring less than 60 per cent marks in your board is 6,865. Now, on basis of your ranking in the board result your percentile will be calculated as below:Number of candidates in your board with aggregate marks less than you*100Total number of candidates in the group= 6865*100 = 50.07 percentile13711Step 2: Scores of all JEE Main canddiates appearing on All India basis are arranged in Merit and their percentile is derived. Here, we assume that the total number of JEE Main eligible candidates on All India basis is 11,53,667. The JEE Main score belonging to the corresponding JEE Main percentile of your Class XII percentile (P) is figured now. Let it be B1Example:As shown in the image below, let's assume that JEE Main marks for a JEE Main percentile which is equal to your board percentile is 48. Thus B1=48.Step 3: Now, scores of all JEE Main eligible canddiates appearing from your Class XII Board are arranged in Merit and again their percetile is derived. Again, the JEE Main score belonging to the corresponding JEE Main percentile of your Class XII percentile (P) is figured. Let it be B2.Example, as shown in the image below, let's assume that JEE Main marks for a JEE Main percentile which is equal to your board percentile is 80. Thus B2=80.Step 4: Now average of B1 and B2 is your actual normalised score. Thus your normalised score isB1+B2 = 48+80 = 642 2Now, assuming that your JEE Main score is 90, the composite score calculated for your JEE Main Rank list will be:(JEE Main Marks)*60+ (Normalised score of Class XII marks)*40100= (90*60)+(64*40) = 5400+2560 = 7960 = 79.60100 100 100Finally, this composite score is arranged in merit order and the rank are derived accordingly.Thus, from the formulae and the process above, you can understand how JEE Main Normalized Score and Class XII Percentile are calculated to derive JEE Main Rank.